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-3x^2+27x-42=0
a = -3; b = 27; c = -42;
Δ = b2-4ac
Δ = 272-4·(-3)·(-42)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-15}{2*-3}=\frac{-42}{-6} =+7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+15}{2*-3}=\frac{-12}{-6} =+2 $
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